[Xorg-driver-geode] Rendering in geode
Huang, FrankR
FrankR.Huang at amd.com
Thu Jul 15 00:05:43 PDT 2010
Jonathan,
So thanks for your all the times help. Although there exists the language barrier(maybe sometimes my explanation is not very clear), I will at my best to describe that in detail to let you understand and give me the guide. I don't want to be in an inexplicit status and but reply I am. So I'll try to make you understand in more detail every time. I have to say you are so full experience in this region that is a fortune for me.
Based on your advice, I do some experiment. As what you said, the source start point is a modulus operation, the example can be seem from:
https://bugs.freedesktop.org/attachment.cgi?id=37062
https://bugs.freedesktop.org/attachment.cgi?id=37063
The source coordinate(22) is out of source picture(20x20), then the new start point is (2,0) instead (0,0).
So I modified my patch and release a new one.
Thanks,
Frank
-----Original Message-----
From: xorg-devel-bounces+frankr.huang=amd.com at lists.x.org [mailto:xorg-devel-bounces+frankr.huang=amd.com at lists.x.org] On Behalf Of Jonathan Morton
Sent: 2010?7?14? 18:45
To: Huang, FrankR
Cc: xorg-driver-geode at lists.x.org; xorg-devel at lists.x.org
Subject: RE: [Xorg-driver-geode] Rendering in geode
On Wed, 2010-07-14 at 09:29 +0800, Huang, FrankR wrote:
> I have some understanding about your explanation. Is that to say if
> the source pixel is out of the source image, the modulus operation
> will be used to get the source pixel to to rendered, not for the
> rendering region.
> Take my example, the srcX is 11. So after the modulus operation, the
> source pixle used to rendering is (11%10, 0), that is (1,0). And
> because the rendering region is 40x40, so it will wrap back the (0,0)
> of the source image for the continuing rendering. Is that correct?
Essentially, yes. I understand there is a slight language barrier here,
but I think your understanding is now correct.
--
------
From: Jonathan Morton
jonathan.morton at movial.com
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